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Math fundamentals

Quick reference for the material in chapter 1 of Ivan Savov's No bullshit guide to math & physics, one block per section. Nothing here is explained; it is the chart you look at once you already know the idea. See also notation and constants, units and conversions.

1.1 Solving equations

Isolate the unknown by undoing operations, applying the same change to both sides.

To undoApplyWatch out
+ c+\,c− c-\,c
× c\times\,c÷ c\div\,cc≠0c \neq 0
x2x^2  \sqrt{\;}two roots: x=±  x = \pm\sqrt{\;}
x\sqrt{x}squarerequires x≥0x \ge 0
xnx^n  n\sqrt[n]{\;}even nn: ±\pm; odd nn: one root
exe^xln⁡\lnargument must be positive
10x10^xlog⁡10\log_{10}
sin⁡,cos⁡,tan⁡\sin, \cos, \tansin⁡−1,cos⁡−1,tan⁡−1\sin^{-1}, \cos^{-1}, \tan^{-1}restrict to the principal range
− c-\,c+ c+\,c
÷ c\div\,c× c\times\,cc≠0c \neq 0
−x-x (negation)−(  )-(\;)its own inverse
1/x1/x1/(  )1/(\;)x≠0x \neq 0; its own inverse
x3x^3  3\sqrt[3]{\;}one root, negatives allowed
∣x∣\lvert x \rvert±(  )\pm(\;)two cases: x=±(  )x = \pm(\;), needs (  )≥0(\;) \ge 0
bxb^xlog⁡b\log_bargument must be positive
ln⁡x\ln xe(  )e^{(\;)}result is always positive
log⁡bx\log_b xb(  )b^{(\;)}
cx\dfrac{c}{x}c(  )\dfrac{c}{(\;)}x≠0x \neq 0; equivalently cross-multiply

Order of operations: brackets, exponents, multiplication and division, addition and subtraction.

SituationMove
unknown on both sidescollect xx terms on one side, constants on the other
unknown inside bracketsexpand, or divide by the bracket's coefficient first
unknown in a denominatormultiply both sides by the denominator (≠0\neq 0)
two fractions equalcross-multiply: ab=cd⇒ad=bc\tfrac{a}{b} = \tfrac{c}{d} \Rightarrow ad = bc
product equals zeroab=0⇒a=0ab = 0 \Rightarrow a = 0 or b=0b = 0
x2x^2 and xx both presentquadratic: rearrange to ax2+bx+c=0ax^2 + bx + c = 0 (1.7)
same unknown under a root and outsideisolate the root, square, check for extraneous roots
donesubstitute back into the original equation

1.2 Numbers

SetSymbolContainsClosed under
naturalN\mathbb{N}0,1,2,3,…0, 1, 2, 3, \ldots++, ×\times
integersZ\mathbb{Z}…,−2,−1,0,1,2,…\ldots, -2, -1, 0, 1, 2, \ldots++, −-, ×\times
rationalQ\mathbb{Q}p/qp/q with p,q∈Zp, q \in \mathbb{Z}, q≠0q \neq 0++, −-, ×\times, ÷\div
realR\mathbb{R}rationals and irrationals (2,π,e\sqrt{2}, \pi, e)limits of sequences
complexC\mathbb{C}a+bia + bi with i2=−1i^2 = -1roots of every polynomial
N⊂Z⊂Q⊂R⊂C\mathbb{N} \subset \mathbb{Z} \subset \mathbb{Q} \subset \mathbb{R} \subset \mathbb{C}

Irrational: cannot be written as p/qp/q; decimal expansion never repeats. Prime: integer greater than 1 whose only divisors are 1 and itself.

1.3 Number representations

FormExampleConvert
fraction38\tfrac{3}{8}divide: 3÷8=0.3753 \div 8 = 0.375
decimal0.3750.3753751000=38\tfrac{375}{1000} = \tfrac{3}{8}
repeating0.3‾0.\overline{3}x=0.3‾x = 0.\overline{3}, 10x−x=310x - x = 3, x=13x = \tfrac{1}{3}
percent37.5%37.5\%÷100\div 100
scientific3.75×10−13.75 \times 10^{-1}mantissa in [1,10)[1, 10), integer exponent
mixed number2122\tfrac{1}{2}=52= \tfrac{5}{2}
prime factors360=23⋅32⋅5360 = 2^3 \cdot 3^2 \cdot 5divide out primes in order

Fraction arithmetic:

ab±cd=ad±bcbd,ab⋅cd=acbd,ab÷cd=ab⋅dc\frac{a}{b} \pm \frac{c}{d} = \frac{ad \pm bc}{bd}, \qquad \frac{a}{b} \cdot \frac{c}{d} = \frac{ac}{bd}, \qquad \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \cdot \frac{d}{c}

1.4 Variables

LettersUsual meaning
x,y,zx, y, zunknowns and coordinates
a,b,ca, b, cknown constants, coefficients
n,m,k,i,jn, m, k, i, jintegers, counters, indices
tttime
θ,ϕ,α,β\theta, \phi, \alpha, \betaangles
f,g,hf, g, hfunctions
λ,μ\lambda, \murates, wavelengths, means
ϵ,δ\epsilon, \deltasmall quantities

Constant: fixed value. Parameter: fixed within one problem, may change between problems. Unknown: the thing to solve for.

1.5 Functions and their inverses

f−1(f(x))=xf^{-1}(f(x)) = x and f(f−1(y))=yf(f^{-1}(y)) = y. Solving f(x)=yf(x) = y means applying f−1f^{-1} to both sides.

f(x)f(x)f−1(y)f^{-1}(y)Domain of f−1f^{-1}
x+cx + cy−cy - call yy
cxcxy/cy/call yy, c≠0c \neq 0
x2x^2±y\pm\sqrt{y}y≥0y \ge 0
x3x^3y3\sqrt[3]{y}all yy
x\sqrt{x}y2y^2y≥0y \ge 0
1/x1/x1/y1/yy≠0y \neq 0
exe^xln⁡y\ln yy>0y > 0
bxb^xlog⁡by\log_b yy>0y > 0
sin⁡x\sin xsin⁡−1y\sin^{-1} y−1≤y≤1-1 \le y \le 1, gives [−π2,π2][-\tfrac{\pi}{2}, \tfrac{\pi}{2}]
cos⁡x\cos xcos⁡−1y\cos^{-1} y−1≤y≤1-1 \le y \le 1, gives [0,π][0, \pi]
tan⁡x\tan xtan⁡−1y\tan^{-1} yall yy, gives (−π2,π2)(-\tfrac{\pi}{2}, \tfrac{\pi}{2})
x−cx - cy+cy + call yy
x/cx/ccycyall yy, c≠0c \neq 0
mx+bmx + b(y−b)/m(y - b)/mall yy, m≠0m \neq 0
−x-x−y-yall yy
xnx^n, odd nnyn\sqrt[n]{y}all yy
xnx^n, even nn±yn\pm\sqrt[n]{y}y≥0y \ge 0
xn\sqrt[n]{x}yny^ny≥0y \ge 0 (even nn), all yy (odd nn)
1/x21/x^2±1/y\pm 1/\sqrt{y}y>0y > 0
∣x∣\lvert x \rvert±y\pm yy≥0y \ge 0
ln⁡x\ln xeye^yall yy
log⁡bx\log_b xbyb^yall yy
10x10^xlog⁡10y\log_{10} yy>0y > 0
sin⁡−1x\sin^{-1} xsin⁡y\sin y−π2≤y≤π2-\tfrac{\pi}{2} \le y \le \tfrac{\pi}{2}
f(g(x))f(g(x))g−1(f−1(y))g^{-1}(f^{-1}(y))undo the outer function first

A function has an inverse only where it is one-to-one; that is why x2x^2 and sin⁡x\sin x need a restricted domain. Graphically, f−1f^{-1} is ff reflected in the line y=xy = x (1.12).

1.6 Basic rules of algebra

RuleStatement
commutativea+b=b+aa + b = b + a, ab=baab = ba
associative(a+b)+c=a+(b+c)(a + b) + c = a + (b + c), (ab)c=a(bc)(ab)c = a(bc)
distributivea(b+c)=ab+aca(b + c) = ab + ac
identitya+0=aa + 0 = a, a⋅1=aa \cdot 1 = a
inversea+(−a)=0a + (-a) = 0, a⋅1a=1a \cdot \tfrac{1}{a} = 1
zero productab=0⇒a=0ab = 0 \Rightarrow a = 0 or b=0b = 0

Expanding and factoring:

(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2(a+b)(a−b)=a2−b2(a+b)3=a3+3a2b+3ab2+b3a3−b3=(a−b)(a2+ab+b2)a3+b3=(a+b)(a2−ab+b2)(x+p)(x+q)=x2+(p+q)x+pq(ax+b)(cx+d)=acx2+(ad+bc)x+bd\begin{aligned} (a + b)^2 &= a^2 + 2ab + b^2 \\ (a - b)^2 &= a^2 - 2ab + b^2 \\ (a + b)(a - b) &= a^2 - b^2 \\ (a + b)^3 &= a^3 + 3a^2 b + 3ab^2 + b^3 \\ a^3 - b^3 &= (a - b)(a^2 + ab + b^2) \\ a^3 + b^3 &= (a + b)(a^2 - ab + b^2) \\ (x + p)(x + q) &= x^2 + (p + q)x + pq \\ (ax + b)(cx + d) &= acx^2 + (ad + bc)x + bd \end{aligned}

Names: in abc+de=0abc + de = 0, the products abcabc and dede are terms, aa, bb, cc, dd, ee are factors, the left side is an expression, the whole thing is an equation.

1.7 Solving quadratic equations

ax2+bx+c=0⟹x=−b±b2−4ac2aax^2 + bx + c = 0 \quad\Longrightarrow\quad x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Discriminant Δ=b2−4ac\Delta = b^2 - 4acRoots
Δ>0\Delta > 0two distinct real roots
Δ=0\Delta = 0one repeated real root x=−b/2ax = -b/2a
Δ<0\Delta < 0two complex conjugate roots
FormExpressionReads off
standardax2+bx+cax^2 + bx + cyy-intercept cc
factoreda(x−r1)(x−r2)a(x - r_1)(x - r_2)roots r1,r2r_1, r_2
vertexa(x−h)2+ka(x - h)^2 + kvertex (h,k)(h, k), h=−b/2ah = -b/2a

Completing the square: x2+bx=(x+b2)2−b24x^2 + bx = \left(x + \tfrac{b}{2}\right)^2 - \tfrac{b^2}{4}. Vieta: r1+r2=−bar_1 + r_2 = -\tfrac{b}{a} and r1r2=car_1 r_2 = \tfrac{c}{a}.

1.8 Exponents

RuleForm
productaman=am+na^m a^n = a^{m+n}
quotientam/an=am−na^m / a^n = a^{m-n}
power of a power(am)n=amn(a^m)^n = a^{mn}
power of a product(ab)n=anbn(ab)^n = a^n b^n
power of a quotient(a/b)n=an/bn(a/b)^n = a^n / b^n
zeroa0=1a^0 = 1 for a≠0a \neq 0
negativea−n=1/ana^{-n} = 1/a^n
fractionala1/n=ana^{1/n} = \sqrt[n]{a}, am/n=amna^{m/n} = \sqrt[n]{a^m}
rootsab=ab\sqrt{ab} = \sqrt{a}\sqrt{b}, a/b=a/b\sqrt{a/b} = \sqrt{a}/\sqrt{b}
onea1=aa^1 = a, 1n=11^n = 1
zero base0n=00^n = 0 for n>0n > 0; 000^0 is left undefined (often taken as 11)
negative fractionala−m/n=1amna^{-m/n} = \dfrac{1}{\sqrt[n]{a^m}}
negative quotient(a/b)−n=(b/a)n(a/b)^{-n} = (b/a)^n
negative base(−a)n=an(-a)^n = a^n for even nn, −an-a^n for odd nn
root of a powerann=∣a∣\sqrt[n]{a^n} = \lvert a \rvert for even nn, =a= a for odd nn
nested rootsanm=amn\sqrt[m]{\sqrt[n]{a}} = \sqrt[mn]{a}
root of a root indexamn=(an)m\sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m
rationalising1a=aa\dfrac{1}{\sqrt{a}} = \dfrac{\sqrt{a}}{a}, 1a+b=a−ba−b\dfrac{1}{\sqrt{a} + \sqrt{b}} = \dfrac{\sqrt{a} - \sqrt{b}}{a - b}
any base as eeax=exln⁡aa^x = e^{x \ln a}
same base equalam=an⇒m=na^m = a^n \Rightarrow m = n for a>0a > 0, a≠1a \neq 1
same exponent equalan=bn⇒a=ba^n = b^n \Rightarrow a = b (odd nn), a=±ba = \pm b (even nn)
scientific notationd.ddd×10nd.ddd \times 10^n, one non-zero digit before the point

Fractional powers with even nn need a≥0a \ge 0 in the reals;   \sqrt{\;} always means the non-negative root.

Not rules: (a+b)n≠an+bn(a + b)^n \neq a^n + b^n, a+b≠a+b\sqrt{a + b} \neq \sqrt{a} + \sqrt{b}, aman≠amna^m a^n \neq a^{mn}, ambn≠(ab)m+na^m b^n \neq (ab)^{m+n}, and (am)n≠amn(a^m)^n \neq a^{m^n} (compare a(mn)a^{(m^n)} with (am)n=amn(a^m)^n = a^{mn}).

1.9 Logarithms

log⁡bx=y\log_b x = y means by=xb^y = x, for b>0b > 0, b≠1b \neq 1, x>0x > 0.

RuleForm
productlog⁡b(xy)=log⁡bx+log⁡by\log_b(xy) = \log_b x + \log_b y
quotientlog⁡b(x/y)=log⁡bx−log⁡by\log_b(x/y) = \log_b x - \log_b y
powerlog⁡b(xn)=nlog⁡bx\log_b(x^n) = n \log_b x
baselog⁡bb=1\log_b b = 1, log⁡b1=0\log_b 1 = 0
inverseblog⁡bx=xb^{\log_b x} = x, log⁡b(bx)=x\log_b(b^x) = x
change of baselog⁡bx=log⁡cxlog⁡cb=ln⁡xln⁡b\log_b x = \dfrac{\log_c x}{\log_c b} = \dfrac{\ln x}{\ln b}
reciprocallog⁡b(1/x)=−log⁡bx\log_b(1/x) = -\log_b x
rootlog⁡bxn=1nlog⁡bx\log_b \sqrt[n]{x} = \dfrac{1}{n}\log_b x
swaplog⁡ba=1log⁡ab\log_b a = \dfrac{1}{\log_a b}
power of baselog⁡bnx=1nlog⁡bx\log_{b^n} x = \dfrac{1}{n}\log_b x, log⁡1/bx=−log⁡bx\log_{1/b} x = -\log_b x
exponent swapxlog⁡by=ylog⁡bxx^{\log_b y} = y^{\log_b x}
equalitylog⁡bx=log⁡by  ⟺  x=y\log_b x = \log_b y \iff x = y
signlog⁡bx<0\log_b x < 0 for 0<x<10 < x < 1, >0> 0 for x>1x > 1 (when b>1b > 1)
solving ax=ca^x = cx=log⁡ac=ln⁡cln⁡ax = \log_a c = \dfrac{\ln c}{\ln a}
solving log⁡bx=c\log_b x = cx=bcx = b^c
any baseax=exln⁡aa^x = e^{x \ln a}, so ln⁡(ax)=xln⁡a\ln(a^x) = x \ln a

Not rules: log⁡b(x+y)≠log⁡bx+log⁡by\log_b(x + y) \neq \log_b x + \log_b y, log⁡b(xy)≠log⁡bx⋅log⁡by\log_b(xy) \neq \log_b x \cdot \log_b y, (log⁡bx)n≠nlog⁡bx(\log_b x)^n \neq n \log_b x, and log⁡bxlog⁡by≠log⁡b(x/y)\dfrac{\log_b x}{\log_b y} \neq \log_b(x/y).

NameNotationBase
naturalln⁡x\ln xe≈2.71828e \approx 2.71828
commonlog⁡x\log x1010
binarylog⁡2x\log_2 x22

1.10 The Cartesian plane

QuantityFormula
pointP=(x,y)P = (x, y)
distanced=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
midpoint(x1+x22,y1+y22)\left(\tfrac{x_1 + x_2}{2}, \tfrac{y_1 + y_2}{2}\right)
slopem=y2−y1x2−x1=ΔyΔxm = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{\Delta y}{\Delta x}
quadrantsI (+,+)(+,+), II (−,+)(-,+), III (−,−)(-,-), IV (+,−)(+,-)

Parallel lines share a slope; perpendicular lines have slopes with m1m2=−1m_1 m_2 = -1.

1.11 Functions

f:A→Bf : A \to B takes each xx in the domain AA to one f(x)f(x) in the codomain BB. The image is the set of values actually produced.

TermMeaning
domaininputs where ff is defined
image / rangeoutputs {f(x):x∈A}\{ f(x) : x \in A \}
composition(g∘f)(x)=g(f(x))(g \circ f)(x) = g(f(x))
one-to-onef(x1)=f(x2)⇒x1=x2f(x_1) = f(x_2) \Rightarrow x_1 = x_2; invertible
evenf(−x)=f(x)f(-x) = f(x), symmetric about the yy-axis
oddf(−x)=−f(x)f(-x) = -f(x), symmetric about the origin
periodicf(x+T)=f(x)f(x + T) = f(x)
zero / rootxx with f(x)=0f(x) = 0; graph crosses the xx-axis
Restriction on the domainReason
x≠0x \neq 0 in 1/x1/xdivision by zero
x≥0x \ge 0 in x\sqrt{x}real square root
x>0x > 0 in ln⁡x\ln xlog of a positive number
x≠π2+nπx \neq \tfrac{\pi}{2} + n\pi in tan⁡x\tan xcos⁡x=0\cos x = 0

1.12 Functions reference

Functionf(x)f(x)DomainImageNotes
linemx+bmx + bR\mathbb{R}R\mathbb{R}slope mm, intercept bb; root −b/m-b/m
squarex2x^2R\mathbb{R}[0,∞)[0, \infty)even; vertex at origin
square rootx\sqrt{x}[0,∞)[0, \infty)[0,∞)[0, \infty)inverse of x2x^2 on x≥0x \ge 0
absolute value∣x∣\lvert x \rvertR\mathbb{R}[0,∞)[0, \infty)=x2= \sqrt{x^2}; V shape
polynomialanxn+⋯+a0a_n x^n + \cdots + a_0R\mathbb{R}depends on degreeat most nn roots; nn roots in C\mathbb{C}
sinesin⁡x\sin xR\mathbb{R}[−1,1][-1, 1]odd; period 2π2\pi; zeros at nπn\pi
cosinecos⁡x\cos xR\mathbb{R}[−1,1][-1, 1]even; period 2π2\pi; =sin⁡(x+π2)= \sin(x + \tfrac{\pi}{2})
tangenttan⁡x\tan xx≠π2+nπx \neq \tfrac{\pi}{2} + n\piR\mathbb{R}odd; period π\pi; =sin⁡x/cos⁡x= \sin x / \cos x
exponentialexe^xR\mathbb{R}(0,∞)(0, \infty)e0=1e^0 = 1; own derivative
natural logln⁡x\ln x(0,∞)(0, \infty)R\mathbb{R}ln⁡1=0\ln 1 = 0, ln⁡e=1\ln e = 1; inverse of exe^x

Shapes, drawn over each function's usual window:

-3-2-1123-2-1123
linex/2 + 1
-3-2-1123-113579
squarex²
2468-1123
square root√x
-3-2-1123-1123
absolute value|x|
-2-112-4-3-2-11234
polynomialx³ − 3x
-3-2-112-11357
exponentialeˣ
12345678-3-2-1123
natural logln x
-2π-ππ2π-11
sinesin x
-2π-ππ2π-11
cosinecos x
-ππ-4-3-2-11234
tangenttan x
12341234
inverses reflect in y = x x² √x y = x

1.13 Function transformations

New functionEffect on the graph of ff
f(x)+cf(x) + cshift up by cc
f(x−c)f(x - c)shift right by cc
af(x)a f(x)stretch vertically by aa (a>1a > 1), squash if 0<a<10 < a < 1
f(x/a)f(x / a)stretch horizontally by aa
−f(x)-f(x)reflect in the xx-axis
f(−x)f(-x)reflect in the yy-axis
f−1(x)f^{-1}(x)reflect in the line y=xy = x

General sinusoid: Asin⁡(ωx+ϕ)+CA \sin(\omega x + \phi) + C has amplitude AA, period 2π/ω2\pi/\omega, phase shift −ϕ/ω-\phi/\omega, vertical offset CC.

Each plot shows ff in the first color and the transformed copies in the others:

-3-2-1123-113579
shifts f(x) = x² f(x) + 2 f(x − 2)
-2π-ππ2π-2-112
stretches f(x) = sin x 2 f(x) f(2x)
-3-2-1123-8-6-4-22468
reflections f(x) = eˣ −f(x) f(−x)
-2π-ππ2π-2-11234
sinusoid sin x 2 sin(2(x − 0.5)) + 1

1.14 Geometry

ShapeArea / surfacePerimeter / volume
triangle12bh\tfrac{1}{2} b ha+b+ca + b + c
squares2s^24s4s
rectangleℓw\ell w2ℓ+2w2\ell + 2w
parallelogrambhb h
trapezoid12(a+b)h\tfrac{1}{2}(a + b) h
circleπr2\pi r^22πr2\pi r
sphere4πr24\pi r^243πr3\tfrac{4}{3}\pi r^3
cylinder2πrh+2πr22\pi r h + 2\pi r^2πr2h\pi r^2 h
coneπrℓ+πr2\pi r \ell + \pi r^213πr2h\tfrac{1}{3}\pi r^2 h
box2(ℓw+wh+ℓh)2(\ell w + w h + \ell h)ℓwh\ell w h

Pythagoras: a2+b2=c2a^2 + b^2 = c^2 for a right triangle with hypotenuse cc. Heron: A=s(s−a)(s−b)(s−c)A = \sqrt{s(s-a)(s-b)(s-c)} with s=a+b+c2s = \tfrac{a+b+c}{2}. Angles in a triangle sum to π\pi; in an nn-gon to (n−2)π(n - 2)\pi.

1.15 Trigonometry

For a right triangle with angle θ\theta, opposite oo, adjacent aa, hypotenuse hh:

sin⁡θ=oh,cos⁡θ=ah,tan⁡θ=oa=sin⁡θcos⁡θ\sin\theta = \frac{o}{h}, \qquad \cos\theta = \frac{a}{h}, \qquad \tan\theta = \frac{o}{a} = \frac{\sin\theta}{\cos\theta}
θ\theta (deg)radsin⁡\sincos⁡\costan⁡\tan
0000001100
3030π/6\pi/612\tfrac{1}{2}32\tfrac{\sqrt{3}}{2}13\tfrac{1}{\sqrt{3}}
4545π/4\pi/422\tfrac{\sqrt{2}}{2}22\tfrac{\sqrt{2}}{2}11
6060π/3\pi/332\tfrac{\sqrt{3}}{2}12\tfrac{1}{2}3\sqrt{3}
9090π/2\pi/21100undefined
180180π\pi00−1-100
2702703π/23\pi/2−1-100undefined

Reciprocals: csc⁡=1/sin⁡\csc = 1/\sin, sec⁡=1/cos⁡\sec = 1/\cos, cot⁡=1/tan⁡\cot = 1/\tan. Unit circle: the point at angle θ\theta is (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta). Degrees to radians: multiply by π/180\pi/180. One full turn is 2π2\pi rad.

Unit circle with the standard angles in degrees and radians and their (cos, sin) coordinates

Any triangle with sides a,b,ca, b, c opposite angles A,B,CA, B, C:

sin⁡Aa=sin⁡Bb=sin⁡Cc,c2=a2+b2−2abcos⁡C\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}, \qquad c^2 = a^2 + b^2 - 2ab\cos C

1.16 Trigonometric identities

sin⁡2θ+cos⁡2θ=11+tan⁡2θ=sec⁡2θsin⁡(a±b)=sin⁡acos⁡b±cos⁡asin⁡bcos⁡(a±b)=cos⁡acos⁡b∓sin⁡asin⁡btan⁡(a±b)=tan⁡a±tan⁡b1∓tan⁡atan⁡bsin⁡2θ=2sin⁡θcos⁡θcos⁡2θ=cos⁡2θ−sin⁡2θ=2cos⁡2θ−1=1−2sin⁡2θsin⁡2θ=12(1−cos⁡2θ)cos⁡2θ=12(1+cos⁡2θ)sin⁡asin⁡b=12[cos⁡(a−b)−cos⁡(a+b)]cos⁡acos⁡b=12[cos⁡(a−b)+cos⁡(a+b)]sin⁡acos⁡b=12[sin⁡(a+b)+sin⁡(a−b)]\begin{aligned} \sin^2\theta + \cos^2\theta &= 1 \\ 1 + \tan^2\theta &= \sec^2\theta \\ \sin(a \pm b) &= \sin a \cos b \pm \cos a \sin b \\ \cos(a \pm b) &= \cos a \cos b \mp \sin a \sin b \\ \tan(a \pm b) &= \frac{\tan a \pm \tan b}{1 \mp \tan a \tan b} \\ \sin 2\theta &= 2 \sin\theta \cos\theta \\ \cos 2\theta &= \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta \\ \sin^2\theta &= \tfrac{1}{2}(1 - \cos 2\theta) \\ \cos^2\theta &= \tfrac{1}{2}(1 + \cos 2\theta) \\ \sin a \sin b &= \tfrac{1}{2}[\cos(a - b) - \cos(a + b)] \\ \cos a \cos b &= \tfrac{1}{2}[\cos(a - b) + \cos(a + b)] \\ \sin a \cos b &= \tfrac{1}{2}[\sin(a + b) + \sin(a - b)] \end{aligned}
SymmetryIdentity
paritysin⁡(−θ)=−sin⁡θ\sin(-\theta) = -\sin\theta, cos⁡(−θ)=cos⁡θ\cos(-\theta) = \cos\theta
cofunctionsin⁡(π2−θ)=cos⁡θ\sin(\tfrac{\pi}{2} - \theta) = \cos\theta, cos⁡(π2−θ)=sin⁡θ\cos(\tfrac{\pi}{2} - \theta) = \sin\theta
half turnsin⁡(θ+π)=−sin⁡θ\sin(\theta + \pi) = -\sin\theta, cos⁡(θ+π)=−cos⁡θ\cos(\theta + \pi) = -\cos\theta
periodsin⁡(θ+2π)=sin⁡θ\sin(\theta + 2\pi) = \sin\theta, tan⁡(θ+π)=tan⁡θ\tan(\theta + \pi) = \tan\theta

1.17 Circles and polar coordinates

QuantityFormula
circle, center originx2+y2=r2x^2 + y^2 = r^2
circle, center (h,k)(h,k)(x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2
parametricx=rcos⁡θx = r\cos\theta, y=rsin⁡θy = r\sin\theta
arc lengths=rθs = r\theta (θ\theta in radians)
sector areaA=12r2θA = \tfrac{1}{2} r^2 \theta
chord length2rsin⁡(θ/2)2r\sin(\theta/2)

Polar (r,θ)(r, \theta) and Cartesian (x,y)(x, y):

x=rcos⁡θ,y=rsin⁡θr=x2+y2,θ=atan2⁡(y,x)\begin{aligned} x &= r\cos\theta, & y &= r\sin\theta \\ r &= \sqrt{x^2 + y^2}, & \theta &= \operatorname{atan2}(y, x) \end{aligned}

1.18 Ellipse

x2a2+y2b2=1(a≥b)\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \qquad (a \ge b)
QuantityFormula
semi-axesaa (major), bb (minor)
foci(±c,0)(\pm c, 0) with c=a2−b2c = \sqrt{a^2 - b^2}
eccentricityε=c/a\varepsilon = c/a, 0≤ε<10 \le \varepsilon < 1
areaπab\pi a b
defining propertysum of distances to the foci is 2a2a
parametricx=acos⁡tx = a\cos t, y=bsin⁡ty = b\sin t
polar (focus at origin)r(θ)=a(1−ε2)1+εcos⁡θr(\theta) = \dfrac{a(1 - \varepsilon^2)}{1 + \varepsilon\cos\theta}

1.19 Parabola

FormVertexOpensFocus / directrix
y=ax2+bx+cy = ax^2 + bx + cx=−b/2ax = -b/2aup if a>0a > 0
y=a(x−h)2+ky = a(x - h)^2 + k(h,k)(h, k)up if a>0a > 0focus (h,k+14a)(h, k + \tfrac{1}{4a}), directrix y=k−14ay = k - \tfrac{1}{4a}
x2=4pyx^2 = 4py(0,0)(0, 0)up if p>0p > 0focus (0,p)(0, p), directrix y=−py = -p
y2=4pxy^2 = 4px(0,0)(0, 0)right if p>0p > 0focus (p,0)(p, 0), directrix x=−px = -p

Defining property: every point is equidistant from the focus and the directrix. Eccentricity ε=1\varepsilon = 1.

1.20 Hyperbola

x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
QuantityFormula
vertices(±a,0)(\pm a, 0)
foci(±c,0)(\pm c, 0) with c=a2+b2c = \sqrt{a^2 + b^2}
asymptotesy=±baxy = \pm \tfrac{b}{a} x
eccentricityε=c/a>1\varepsilon = c/a > 1
defining propertydifference of distances to the foci is 2a2a
vertical formy2a2−x2b2=1\tfrac{y^2}{a^2} - \tfrac{x^2}{b^2} = 1, opens up and down
rectangularxy=kxy = k, asymptotes are the axes

Conics by eccentricity: circle 00, ellipse 0<ε<10 < \varepsilon < 1, parabola 11, hyperbola >1> 1.

1.21 Solving systems of linear equations

MethodSteps
substitutionsolve one equation for a variable; substitute into the other
eliminationscale equations so a variable cancels when they are added
graphicalthe solution is where the lines cross
determinantCramer's rule, below

For a1x+b1y=c1a_1 x + b_1 y = c_1 and a2x+b2y=c2a_2 x + b_2 y = c_2:

D=a1b2−a2b1,x=c1b2−c2b1D,y=a1c2−a2c1DD = a_1 b_2 - a_2 b_1, \qquad x = \frac{c_1 b_2 - c_2 b_1}{D}, \qquad y = \frac{a_1 c_2 - a_2 c_1}{D}
DDSolutions
D≠0D \neq 0exactly one
D=0D = 0none (parallel lines) or infinitely many (same line)

1.22 Compound interest

SchemeAmount after tt years
simpleA=P(1+rt)A = P(1 + rt)
compounded yearlyA=P(1+r)tA = P(1 + r)^t
compounded nn times a yearA=P(1+rn)ntA = P\left(1 + \tfrac{r}{n}\right)^{nt}
continuousA=PertA = Pe^{rt}

Effective annual rate: (1+rn)n−1(1 + \tfrac{r}{n})^n - 1. Doubling time: t=ln⁡2ln⁡(1+r)≈72100rt = \dfrac{\ln 2}{\ln(1 + r)} \approx \dfrac{72}{100r}. Present value: P=A(1+r)−tP = A(1 + r)^{-t}.

1.23 Set notation

SymbolReads
{a,b,c}\{a, b, c\}the set containing aa, bb, cc
{x:P(x)}\{x : P(x)\}the set of xx such that P(x)P(x)
x∈Ax \in Axx is an element of AA
x∉Ax \notin Axx is not an element of AA
A⊆BA \subseteq BAA is a subset of BB
A⊂BA \subset Bproper subset
A∪BA \cup Bunion: in AA or BB
A∩BA \cap Bintersection: in both
A∖BA \setminus Bdifference: in AA, not in BB
Aˉ\bar{A} or AcA^ccomplement
∅\varnothingthe empty set
∣A∣\lvert A \rvertnumber of elements
A×BA \times BCartesian product: pairs (a,b)(a, b)
∀\forall, ∃\existsfor all, there exists
IntervalSet
[a,b][a, b]{x:a≤x≤b}\{x : a \le x \le b\}
(a,b)(a, b){x:a<x<b}\{x : a < x < b\}
[a,b)[a, b){x:a≤x<b}\{x : a \le x < b\}
[a,∞)[a, \infty){x:x≥a}\{x : x \ge a\}

Laws: A∪B=B∪AA \cup B = B \cup A; A∩(B∪C)=(A∩B)∪(A∩C)A \cap (B \cup C) = (A \cap B) \cup (A \cap C); De Morgan: A∪B‾=Aˉ∩Bˉ\overline{A \cup B} = \bar{A} \cap \bar{B} and A∩B‾=Aˉ∪Bˉ\overline{A \cap B} = \bar{A} \cup \bar{B}.

1.24 Math problems

A checklist for working through the chapter's problem sets.

StepDo
readname the unknown; write down what is given with units
modelpick the equation or identity that links given and unknown
solveisolate the unknown symbolically before substituting numbers
checkunits, sign, magnitude, special cases (00, ∞\infty, symmetry)
verifysubstitute the answer back into the original equation

References